hummingwolf (
hummingwolf) wrote2007-02-09 10:10 am
Math Terminology Question
Now that half of you have been scared away by the subject line:
Okay, numbers which are the sums of the natural numbers from 1 through [whatever] are called triangular numbers. You can see why if you do a little dot drawing of, say, the sum of the numbers from 1 through 4:
*
**
***
****
The above shows you that 10 is a nice triangular number, which you already knew if you've ever been bowling. Other triangular numbers include 36 (the sum of the numbers from 1 through 8) and 666 (sum of numbers from 1 through 36).
Here's my question: Is there a general name for the numbers made up of sums of evenly-spaced numbers? Like the sum of all the odd numbers between 15 and 71, or the sums of the numbers in this series:
-23
-12
-1
10
21
32
43
54
65
etc.?
I've long known how to figure out what the values of the numbers are, but have no idea what to call them.
Okay, numbers which are the sums of the natural numbers from 1 through [whatever] are called triangular numbers. You can see why if you do a little dot drawing of, say, the sum of the numbers from 1 through 4:
*
**
***
****
The above shows you that 10 is a nice triangular number, which you already knew if you've ever been bowling. Other triangular numbers include 36 (the sum of the numbers from 1 through 8) and 666 (sum of numbers from 1 through 36).
Here's my question: Is there a general name for the numbers made up of sums of evenly-spaced numbers? Like the sum of all the odd numbers between 15 and 71, or the sums of the numbers in this series:
-23
-12
-1
10
21
32
43
54
65
etc.?
I've long known how to figure out what the values of the numbers are, but have no idea what to call them.

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bn + ((n(n-1))/2)k.
In your example above, straight addition gives 189.
b = -23, k = 11, and n = 9, and plugging these in the above formula also gives 189. Notice that the (n-1)st triangular sum appears as ((n(n-1))/2). :)
no subject
The way I actually learned to figure them was, if I knew I wanted to add those numbers up to some number n (not the number of terms, but, e.g., number 65 on that list), I could use
((n+b)(n+k-b)) / 2k
And the sum of the sums is
((n+2b)(n+k-b)(n+2k-b)) / 2*3k2
And the sum of the sums of sums is something you can surely figure out so I won't bother typing up any more. :-)
no subject